Alfred, Allegany, New York
| Latitude | 42°14'18.85"N |
| Longitude | 77°47'20.72"W |
| City | Alfred |
| County | Allegany |
| State/ Province | New York |
| Enclosed By | |
|---|---|
| Allegany | |
| Place Encloses |
Place Map
Source References
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Marc Wick: GeoNames
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- Page: GeoNames ID: 5106961
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